0=-16t^2+35.52

Solution for 0=-16t^2+35.52 equation:

0=-16t^2+35.52

We move all terms to the left:

0-(-16t^2+35.52)=0

We add all the numbers together, and all the variables

-(-16t^2+35.52)=0

We get rid of parentheses

16t^2-35.52=0

a = 16; b = 0; c = -35.52;
Δ = b2-4ac
Δ = 02-4·16·(-35.52)
Δ = 2273.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2273.28}}{2*16}=\frac{0-\sqrt{2273.28}}{32}
=-\frac{\sqrt{}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2273.28}}{2*16}=\frac{0+\sqrt{2273.28}}{32}
=\frac{\sqrt{}}{32}
$